Upon reaction with CH_3MgBr followed by proto | vedclass

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(C) The reaction of a Grignard reagent $(RMgX)$ with formaldehyde $(HCHO)$ followed by acid hydrolysis $(H_3O^+)$ yields a primary alcohol with one mo

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$HCHO$

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(C) The reaction of a Grignard reagent $(RMgX)$ with formaldehyde $(HCHO)$ followed by acid hydrolysis $(H_3O^+)$ yields a primary alcohol with one more carbon atom than the Grignard reagent.For the production of ethanol $(CH_3CH_2OH)$,which has two carbon atoms,the Grignard reagent $CH_3MgBr$ (one carbon) must react with formaldehyde ($HCHO$,one carbon).The reaction is as follows:$HCHO + CH_3MgBr \rightarrow H-C(H)(CH_3)-OMgBr$$H-C(H)(CH_3)-OMgBr + H_3O^+ \rightarrow CH_3CH_2OH + Mg(OH)Br$Thus,the correct compound is formaldehyde $(HCHO)$.

Upon reaction with $CH_3MgBr$ followed by protonation,the compound that produces ethanol is

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