Using a simple pendulum experiment, g is dete | vedclass

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(B) The time period $T$ of a simple pendulum is given by the formula: $T = 2\pi \sqrt{\frac{L}{g}}$.Squaring both sides, we get: $T^2 = \frac{4\pi^2 L

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(B) The time period $T$ of a simple pendulum is given by the formula: $T = 2\pi \sqrt{\frac{L}{g}}$.Squaring both sides, we get: $T^2 = \frac{4\pi^2 L}{g}$.Taking the reciprocal of both sides, we get: $\frac{1}{T^2} = \frac{g}{4\pi^2 L}$.This equation is of the form $y = \frac{k}{x}$, where $y = \frac{1}{T^2}$, $x = L$, and $k = \frac{g}{4\pi^2}$ is a constant.This represents a rectangular hyperbola, which corresponds to the plot shown in option $B$.

Using a simple pendulum experiment, $g$ is determined by measuring its time period $T$. Which of the following plots represents the correct relation between the pendulum length $L$ and time period $T$?

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