For the given reaction,the value of x is: | vedclass

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(B) The reaction involves the cleavage of ethers and the reaction of functional groups with $HI$.$1$. The molecule contains two ether linkages: one ar

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The reaction involves the cleavage of ethers and the reaction of functional groups with $HI$.$1$. The molecule contains two ether linkages: one aryl-alkyl ether $(-OCH_3)$ and one diaryl ether ($-O-$ linkage between the two aromatic rings).$2$. The aryl-alkyl ether $(-OCH_3)$ reacts with $HI$ to form a phenol and $CH_3I$ ($1$ mole of $HI$ used).$3$. The diaryl ether linkage is generally resistant to cleavage by $HI$ under normal conditions.$4$. The primary alcohol group $(-CH_2OH)$ reacts with $HI$ to form an alkyl iodide $(-CH_2I)$ and water ($1$ mole of $HI$ used).$5$. The alkene group $(-CH=CH_2)$ reacts with $HI$ via electrophilic addition to form an alkyl iodide $(-CH(I)-CH_3)$ ($1$ mole of $HI$ used).$6$. Total moles of $HI$ required $(x)$ = $1$ (for ether) + $1$ (for alcohol) + $1$ (for alkene) = $3$ moles.Therefore,the value of $x$ is $3$.

For the given reaction,the value of $x$ is:

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