(B) We know that $16$ can be written as a power of $2$,specifically $16 = 2^4$.Using the logarithmic property $\log_{b} (a^n) = n \log_{b} a$,we have:

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(B) We know that $16$ can be written as a power of $2$,specifically $16 = 2^4$.Using the logarithmic property $\log_{b} (a^n) = n \log_{b} a$,we have:$\log _{2} 16 = \log _{2} (2^4)$$= 4 \log _{2} 2$Since $\log _{b} b = 1$,we have $\log _{2} 2 = 1$.Therefore,$4 \times 1 = 4$.