The value of (256)^{0.16} times (256)^{0.09} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Using the law of exponents,$a^m 	imes a^n = a^{m+n}$.Given expression: $(256)^{0.16} 	imes (256)^{0.09} = (256)^{0.16 + 0.09}$.Adding the expone

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) Using the law of exponents,$a^m 	imes a^n = a^{m+n}$.Given expression: $(256)^{0.16} 	imes (256)^{0.09} = (256)^{0.16 + 0.09}$.Adding the exponents: $(256)^{0.25}$.Since $0.25 = \frac{1}{4}$,we have $(256)^{\frac{1}{4}}$.Expressing $256$ as a power of $4$: $256 = 4^4$.Therefore,$(4^4)^{\frac{1}{4}} = 4^{4 	imes \frac{1}{4}} = 4^1 = 4$.Hence,the correct option is $A$.

The value of $(256)^{0.16} \times (256)^{0.09}$ is

Similar Questions

Express $0.5\overline{7}$ in the form $\frac{p}{q}$,where $p$ and $q$ are integers and $q \neq 0$.

If $a = 5 + 2\sqrt{6}$ and $b = \frac{1}{a}$,then what will be the value of $a^2 + b^2$?

The value of $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is equal to

Find three different irrational numbers between the rational numbers $\frac{1}{3}$ and $\frac{7}{9}$.

Fill in the blank to make the following statement true:
$(64)^{-\frac{1}{6}} = \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module