(B) The correct option is $(B)$.$Cu$ (Copper) shows variable valency (e.g.,$+1$ and $+2$) due to the presence of vacant $d-$orbitals in its electronic

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(B) The correct option is $(B)$.$Cu$ (Copper) shows variable valency (e.g.,$+1$ and $+2$) due to the presence of vacant $d-$orbitals in its electronic configuration,which allows for the participation of $d-$electrons in bonding.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Valency and oxidation state

Easy

Variable valency is shown by

A
$Na$
B
$Cu$
C
$Mg$
D
$Al$

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Class 11 Questions

Class 11

Chemistry Questions

Chapter

Classification of Elements and Periodicity in Properties

Subtopic

Valency and oxidation state

Which of the following elements exhibits a valency of $2$?

Easy

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The formula of the oxide of an element $M$ having $IE_1 = 100 \ kJ/mol$,$IE_2 = 250 \ kJ/mol$ and $IE_3 = 1500 \ kJ/mol$ should be:

Medium

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Which one of the following elements shows both positive and negative oxidation states?

Medium

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Assertion : $HClO_4$ is a stronger acid than $HClO_3$.
Reason : Oxidation state of $Cl$ in $HClO_4$ is $+VII$ and in $HClO_3$ is $+V$.

DifficultAIIMS 2004

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Consider the following information about elements $P$ and $Q$:

Element Period and Group

$Q$ Period $2$,Group $15$

$P$ Period $3$,Group $2$

Then the formula of the compound formed by $P$ and $Q$ elements is:

Medium

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Element	Period and Group
$Q$	Period $2$,Group $15$
$P$	Period $3$,Group $2$

Variable valency is shown by

Similar Questions

Which of the following elements exhibits a valency of $2$?

The formula of the oxide of an element $M$ having $IE_1 = 100 \ kJ/mol$,$IE_2 = 250 \ kJ/mol$ and $IE_3 = 1500 \ kJ/mol$ should be:

Which one of the following elements shows both positive and negative oxidation states?

Assertion : $HClO_4$ is a stronger acid than $HClO_3$.Reason : Oxidation state of $Cl$ in $HClO_4$ is $+VII$ and in $HClO_3$ is $+V$.

Consider the following information about elements $P$ and $Q$: Element Period and Group $Q$ Period $2$,Group $15$ $P$ Period $3$,Group $2$ Then the formula of the compound formed by $P$ and $Q$ elements is:

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Assertion : $HClO_4$ is a stronger acid than $HClO_3$.
Reason : Oxidation state of $Cl$ in $HClO_4$ is $+VII$ and in $HClO_3$ is $+V$.

Consider the following information about elements $P$ and $Q$:

Element Period and Group

$Q$ Period $2$,Group $15$

$P$ Period $3$,Group $2$

Then the formula of the compound formed by $P$ and $Q$ elements is: