Velocity of sound waves in air is 330 ,m/s. F | vedclass

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(C) Given: Velocity $v = 330 \,m/s$, path difference $\Delta x = 40 \,cm = 0.4 \,m$, and phase difference $\Delta \phi = 1.6 \pi$.We know the relation

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$660$

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(C) Given: Velocity $v = 330 \,m/s$, path difference $\Delta x = 40 \,cm = 0.4 \,m$, and phase difference $\Delta \phi = 1.6 \pi$.We know the relationship between phase difference and path difference is given by $\Delta \phi = \frac{2 \pi}{\lambda} \Delta x$.Substituting the values: $1.6 \pi = \frac{2 \pi}{0.4} \Delta x$ is not needed directly, instead use $\lambda = \frac{v}{f}$.Thus, $\Delta \phi = \frac{2 \pi f}{v} \Delta x$.Rearranging for frequency $f$: $f = \frac{\Delta \phi \cdot v}{2 \pi \cdot \Delta x}$.Substituting the values: $f = \frac{1.6 \pi \cdot 330}{2 \pi \cdot 0.4}$.$f = \frac{1.6 \cdot 330}{0.8} = 2 \cdot 330 = 660 \,Hz$.

Velocity of sound waves in air is $330 \,m/s$. For a particular sound wave in air, a path difference of $40 \,cm$ is equivalent to a phase difference of $1.6 \pi$. The frequency of this wave is: (in $\,Hz$)

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