Verify whether the given value of x is a solu | vedclass

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(A) To verify if $x = \frac{2}{3}$ is a solution,substitute the value of $x$ into the quadratic equation $6x^{2} - x - 2 = 0$.$LHS$ = $6(\frac{2}{3})^

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Yes,it is a solution.

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(A) To verify if $x = \frac{2}{3}$ is a solution,substitute the value of $x$ into the quadratic equation $6x^{2} - x - 2 = 0$.$LHS$ = $6(\frac{2}{3})^{2} - (\frac{2}{3}) - 2$$LHS$ = $6(\frac{4}{9}) - \frac{2}{3} - 2$$LHS$ = $\frac{24}{9} - \frac{2}{3} - 2$$LHS$ = $\frac{8}{3} - \frac{2}{3} - 2$$LHS$ = $\frac{6}{3} - 2$$LHS$ = $2 - 2 = 0$Since $LHS$ = $RHS$,$x = \frac{2}{3}$ is a solution of the given quadratic equation.

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $6x^{2} - x - 2 = 0; x = \frac{2}{3}$

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