Verify whether the given value of x is a solu | vedclass

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(A) To verify if $x = -\frac{1}{2}$ is a solution,substitute the value into the left-hand side $(LHS)$ of the equation.$LHS$ = $\frac{1}{3 - 2(-\frac{

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Yes,it is a solution.

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(A) To verify if $x = -\frac{1}{2}$ is a solution,substitute the value into the left-hand side $(LHS)$ of the equation.$LHS$ = $\frac{1}{3 - 2(-\frac{1}{2})} + \frac{1}{5 + 2(-\frac{1}{2})}$$LHS$ = $\frac{1}{3 - (-1)} + \frac{1}{5 + (-1)}$$LHS$ = $\frac{1}{3 + 1} + \frac{1}{5 - 1}$$LHS$ = $\frac{1}{4} + \frac{1}{4}$$LHS$ = $\frac{2}{4} = \frac{1}{2}$Since $LHS$ = $RHS$ (which is $\frac{1}{2}$),the given value $x = -\frac{1}{2}$ is a solution of the quadratic equation.

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $\frac{1}{3-2x} + \frac{1}{5+2x} = \frac{1}{2}$; $x = -\frac{1}{2}$.

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