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(A) To verify if $x = -\frac{1}{3}$ is a zero of the polynomial $p(x) = 3x + 1$,we substitute $x = -\frac{1}{3}$ into the polynomial.$p\left(-\frac{1}

Vedclass · Accepted Answer

Yes,it is a zero.

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(A) To verify if $x = -\frac{1}{3}$ is a zero of the polynomial $p(x) = 3x + 1$,we substitute $x = -\frac{1}{3}$ into the polynomial.$p\left(-\frac{1}{3}\right) = 3\left(-\frac{1}{3}\right) + 1$$p\left(-\frac{1}{3}\right) = -1 + 1$$p\left(-\frac{1}{3}\right) = 0$Since the value of the polynomial at $x = -\frac{1}{3}$ is $0$,it is confirmed that $x = -\frac{1}{3}$ is a zero of the given polynomial.

Verify whether the following is a zero of the polynomial indicated against it:
$p(x) = 3x + 1, \, x = -\frac{1}{3}$

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Verify whether the following is a zero of the polynomial indicated against it:$p(x) = 3x + 1, \, x = -\frac{1}{3}$