Vessel-1 contains w_2 g of a non-volatile so | vedclass

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Question

(A) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$,where $m$ is the molality.For Vessel-$1$: $(\Delta T_b)_1 = i_1

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(A) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$,where $m$ is the molality.For Vessel-$1$: $(\Delta T_b)_1 = i_1 	imes K_b 	imes \frac{w_2 / GMM_X}{w_1 / 1000}$.For Vessel-$2$: $(\Delta T_b)_2 = i_2 	imes K_b 	imes \frac{w_2 / GMM_Y}{w_1 / 1000}$.Taking the ratio: $\frac{(\Delta T_b)_1}{(\Delta T_b)_2} = \frac{i_1}{i_2} 	imes \frac{GMM_Y}{GMM_X}$.Given $GMM_X = 0.8 	imes GMM_Y$ and $i_1 = 1.2 	imes i_2$.Substituting these values: $\frac{(\Delta T_b)_1}{(\Delta T_b)_2} = \frac{1.2 	imes i_2}{i_2} 	imes \frac{GMM_Y}{0.8 	imes GMM_Y} = \frac{1.2}{0.8} = 1.5$.Therefore,the percentage is $1.5 	imes 100 = 150 \%$.

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