Volume of a gas at STP is 1.12 times 10^{-7} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) At $STP$,$22400 \ cc$ of any gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number).Number of molecules = $\frac{	ext{Given volume}}{\

Vedclass · Accepted Answer

$3.01 	imes 10^{12}$

Vedclass · Answer

(B) At $STP$,$22400 \ cc$ of any gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number).Number of molecules = $\frac{	ext{Given volume}}{	ext{Molar volume at } STP} 	imes N_A$Number of molecules = $\frac{1.12 	imes 10^{-7} \ cc}{22400 \ cc/mol} 	imes 6.022 	imes 10^{23} 	ext{ molecules/mol}$Number of molecules = $\frac{1.12 	imes 6.022}{22400} 	imes 10^{16} \approx 3.01 	imes 10^{12}$ molecules.

Volume of a gas at $STP$ is $1.12 \times 10^{-7} \ cc$. Calculate the number of molecules in it.

Similar Questions

The Avogadro number is defined as ......

$5.6 \, L$ of oxygen at $STP$ contains .............

One atom of an element weighs $3.32 \times 10^{-23} \ g$. How many gram atoms are there in $20 \ kg$ of the element?

What is the numerical value of $\frac{N}{n}$? (Where $N$ is the number of molecules in a given gas sample and $n$ is the number of moles of the gas.)

Find the number of moles present in $0.448 \ L$ of dihydrogen at $STP$. (in $mol$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module