(C) According to Charles's Law,at constant pressure,$V \propto T$. Thus,$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$. Given: $V_{1} = 200 \, cm^{3}$,$T

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(C) According to Charles's Law,at constant pressure,$V \propto T$. Thus,$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$. Given: $V_{1} = 200 \, cm^{3}$,$T_{1} = 17 + 273 = 290 \, K$,$T_{2} = 47 + 273 = 320 \, K$. Substituting the values: $\frac{200}{290} = \frac{V_{2}}{320}$. $V_{2} = \frac{200 \times 320}{290} = 220.68 \, cm^{3} \approx 220.6 \, cm^{3}$.

Class 11 Chemistry States of Matter Ideal gas equation and Related gas laws

Medium

Volume of a given mass of gas at $17 \, ^oC$ is measured as $200 \, cm^3$. The volume of the same mass of that gas at same pressure and at temperature of $47 \, ^oC$ will be .............. $cm^{3}$

A
$77.5$
B
$13.45$
C
$220.6$
D
$320$

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States of Matter

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Ideal gas equation and Related gas laws

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Medium

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MediumAP EAMCET 2007

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DifficultAIPMT 2010

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Explain the effect of Boyle's Law.

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Volume of a given mass of gas at $17 \, ^oC$ is measured as $200 \, cm^3$. The volume of the same mass of that gas at same pressure and at temperature of $47 \, ^oC$ will be .............. $cm^{3}$

Similar Questions

Two separate identical containers contain Gas $A$ $(Mw = 40 \ g \ mol^{-1})$ and gas $B$ $(Mw = x \ g \ mol^{-1})$ in the mass ratio $5 : 8$ under similar conditions of temperature and pressure. The value of $x$ is $:-$

An ideal gas weighing $9.0 \ g$ occupies a volume of $8.2 \ L$ at $300 \ K$ and $1 \ atm$ pressure. The molar mass of the gas is .....

$A$ certain mass of a gas occupies a volume of $2 \,L$ at $STP$. To what temperature must the gas be heated to double its volume, keeping the pressure constant?

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