The volume-temperature graph at atmospheric p | vedclass

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(A) According to Charles's Law,for a gas at constant pressure,the volume $V_T$ at temperature $T$ $(^{\circ}C)$ is given by the relation:$V_T = V_0 \l

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(A) According to Charles's Law,for a gas at constant pressure,the volume $V_T$ at temperature $T$ $(^{\circ}C)$ is given by the relation:$V_T = V_0 \left( 1 + \frac{T}{273} \right)$$V_T = V_0 + \left( \frac{V_0}{273} \right) T$Comparing this with the equation of a straight line $y = mx + c$,where $y = V_T$,$x = T$,$m = \frac{V_0}{273}$ (slope),and $c = V_0$ (y-intercept).Since $V_0 > 0$,the graph is a straight line with a positive y-intercept and a positive slope. This corresponds to the graph shown in option $A$.

The volume-temperature graph at atmospheric pressure for a monoatomic gas ($V$ in $m^3$,$T$ in $^{\circ}C$) is:

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