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(C) The formula for capillary rise is given by $h = \frac{2T \cos 	heta}{r ho g}$.Assuming the contact angle $	heta = 0^\circ$ for water in a glas

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(C) The formula for capillary rise is given by $h = \frac{2T \cos 	heta}{r ho g}$.Assuming the contact angle $	heta = 0^\circ$ for water in a glass capillary,$\cos 0^\circ = 1$.Given: $h = 3\, cm = 3 	imes 10^{-2}\, m$,$T = 75 	imes 10^{-3}\, N/m$,$ho = 10^3\, kg/m^3$,and $g = 10\, m/s^2$.Substituting the values: $3 	imes 10^{-2} = \frac{2 	imes 75 	imes 10^{-3}}{r 	imes 10^3 	imes 10}$.$3 	imes 10^{-2} = \frac{150 	imes 10^{-3}}{r 	imes 10^4} = \frac{15 	imes 10^{-3}}{r 	imes 10^3} = \frac{15 	imes 10^{-6}}{r}$.$r = \frac{15 	imes 10^{-6}}{3 	imes 10^{-2}} = 5 	imes 10^{-4}\, m = 0.5\, mm$.The diameter $D = 2r = 2 	imes 0.5\, mm = 1.0\, mm$.

Water rises in a capillary tube to a height of $3\, cm$ when one end is dipped vertically in it. If the surface tension of water is $75 \times 10^{-3}\, N/m$,then the diameter of the capillary tube will be....... $mm$. (Assume $g = 10\, m/s^2$)

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