Water rises to a height of $2 \,cm$ in a capillary tube. If the cross-sectional area of the tube is reduced to $\frac{1}{16}^{\text{th}}$ of the initial area, then water will rise to a height of: (in $\,cm$)

In a capillary tube of radius '$R$',a straight thin metal wire of radius '$r$' is inserted symmetrically and one end of the combination is dipped vertically in water such that the lower end of the capillary and the thin wire are at the same level. If '$T$' is the surface tension of water and '$\rho$' is the density of water, then the rise of water in the capillary is:

The heat evolved for the rise of water when one end of the capillary tube of radius $r$ is immersed vertically into water is (Assume surface tension $= T$ and density of water to be $\rho$)

If a capillary tube is tilted to $45^o$ and $60^o$ from the vertical,then the ratio of the lengths $l_1$ and $l_2$ of the liquid columns in it will be:

Two long capillary tubes $A$ and $B$ of radius $R_B > R_A$ are dipped in the same liquid. Then:

When a part of a straight capillary tube is placed vertically in a liquid, the liquid rises up to a certain height $h$. If the inner radius of the capillary tube, density of the liquid, and surface tension of the liquid decrease by $1\%$ each, then the height of the liquid in the tube will change by . . . . . . $\%$.