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(C) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$,where $h$ is Planck's constant,$m$ is the mass

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Decreases with an increase in the speed of the electron.

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(C) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$,where $h$ is Planck's constant,$m$ is the mass of the electron,and $v$ is its velocity (speed). From this relation,it is clear that $\lambda \propto \frac{1}{v}$. Therefore,as the speed $(v)$ of the electron increases,the wavelength $(\lambda)$ associated with it decreases.

The wavelength associated with the motion of an electron:

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