Wavenumber for a radiation having 5800 mathr | vedclass

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Question

(A) The wavenumber $(\bar{
u})$ is defined as the reciprocal of wavelength $(\lambda)$: $\bar{
u} = \frac{1}{\lambda}$ Given $\lambda = 5800 \ \math

Vedclass · Accepted Answer

$1724$

Vedclass · Answer

(A) The wavenumber $(\bar{
u})$ is defined as the reciprocal of wavelength $(\lambda)$: $\bar{
u} = \frac{1}{\lambda}$ Given $\lambda = 5800 \ \mathring{A} = 5800 	imes 10^{-8} \ cm = 5.8 	imes 10^{-5} \ cm$. $\bar{
u} = \frac{1}{5.8 	imes 10^{-5} \ cm} = 17241.37 \ cm^{-1}$. We are given $\bar{
u} = x 	imes 10 \ cm^{-1}$. So,$x 	imes 10 = 17241.37$. $x = 1724.137 \approx 1724$.

Wavenumber for a radiation having $5800 \ \mathring{A}$ wavelength is $x \times 10 \ cm^{-1}$. The value of $x$ is . . . . . . . .

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