We wish to obtain an erect image of an object,using a concave mirror of focal length $15\, cm$. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.
(N/A) The range of the object distance should be between $0\, cm$ and $15\, cm$ (i.e.,between the pole $P$ and the principal focus $F$).
$A$ concave mirror produces an erect image only when the object is placed between its pole $(P)$ and the principal focus $(F)$.
The nature of the image formed is virtual and erect.
The image is larger (magnified) than the object.
The ray diagram showing the image formation is provided in the image below.
$A$ concave mirror produces an erect image only when the object is placed between its pole $(P)$ and the principal focus $(F)$.
The nature of the image formed is virtual and erect.
The image is larger (magnified) than the object.
The ray diagram showing the image formation is provided in the image below.
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Material medium Refractive index Air $1.0003$ Ice $1.31$ Water $1.33$ Alcohol $1.36$ Kerosene $1.44$ Fused quartz $1.46$ Turpentine oil $1.47$ Benzene $1.50$ Crown glass $1.52$ Canada Balsam $1.53$ Rock salt $1.54$ Carbon disulphide $1.63$ Dense flint glass $1.65$ Ruby $1.71$ Sapphire $1.77$ Diamond $2.42$
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| Air | $1.0003$ |
| Ice | $1.31$ |
| Water | $1.33$ |
| Alcohol | $1.36$ |
| Kerosene | $1.44$ |
| Fused quartz | $1.46$ |
| Turpentine oil | $1.47$ |
| Benzene | $1.50$ |
| Crown glass | $1.52$ |
| Canada Balsam | $1.53$ |
| Rock salt | $1.54$ |
| Carbon disulphide | $1.63$ |
| Dense flint glass | $1.65$ |
| Ruby | $1.71$ |
| Sapphire | $1.77$ |
| Diamond | $2.42$ |
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Support your answer with a reason.
$(a)$ Headlights of a car
$A$ spherical mirror and a thin spherical lens have each a focal length of $-15\,cm$. The mirror and the lens are likely to be
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