Wien's constant is 2892 times 10^{-6} text{ m | vedclass

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(D) According to Wien's displacement law,the product of the wavelength of maximum emission $\lambda_m$ and the absolute temperature $T$ of a black bod

Vedclass · Accepted Answer

$200$

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(D) According to Wien's displacement law,the product of the wavelength of maximum emission $\lambda_m$ and the absolute temperature $T$ of a black body is a constant,known as Wien's constant $(b)$.$\lambda_m T = b$Given:$b = 2892 	imes 10^{-6} 	ext{ m K}$$\lambda_m = 14.46 	ext{ microns} = 14.46 	imes 10^{-6} 	ext{ m}$Substituting the values into the formula:$T = \frac{b}{\lambda_m} = \frac{2892 	imes 10^{-6}}{14.46 	imes 10^{-6}}$$T = \frac{2892}{14.46} = 200 	ext{ K}$Thus,the surface temperature of the moon is $200 	ext{ K}$.

Wien's constant is $2892 \times 10^{-6} \text{ m K}$ and the value of $\lambda_m$ from the moon is $14.46 \text{ microns}$. What is the surface temperature of the moon in $K$?

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