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(C) To find the approximate value,we round the numbers to the nearest whole numbers:$\frac{1810}{24} 	imes 8 + 11 	imes 19 = x - 306$First,calculate

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$1118$

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(C) To find the approximate value,we round the numbers to the nearest whole numbers:$\frac{1810}{24} 	imes 8 + 11 	imes 19 = x - 306$First,calculate the division and multiplication:$\frac{1810}{24} \approx 75.416$$75.416 	imes 8 \approx 603.33$$11 	imes 19 = 209$Now,substitute these values into the equation:$603 + 209 = x - 306$$812 = x - 306$Solve for $x$:$x = 812 + 306$$x = 1118$

What approximate value will come in place of the question mark $(?)$ in the given equation? (You are not expected to calculate the exact value)
$\frac{1810}{24.05} \times 7.95 + 11.02 \times 18.88 = ? - 306$

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What approximate value will come in place of the question mark $(?)$ in the given equation? (You are not expected to calculate the exact value)$\frac{1810}{24.05} \times 7.95 + 11.02 \times 18.88 = ? - 306$