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(B) $1$. In the presence of a Lewis acid like $FeCl_3$,benzene undergoes electrophilic aromatic substitution with excess $Cl_2$ to form hexachlorobenz

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$HCB$ and $BHC$

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(B) $1$. In the presence of a Lewis acid like $FeCl_3$,benzene undergoes electrophilic aromatic substitution with excess $Cl_2$ to form hexachlorobenzene $(C_6Cl_6)$. Thus,$A$ is $HCB$ (hexachlorobenzene).$2$. In the presence of ultraviolet light $(h
u)$,benzene undergoes free-radical addition with excess $Cl_2$ to form benzene hexachloride $(C_6H_6Cl_6)$,commonly known as $BHC$ or gammaxene. Thus,$B$ is $BHC$ (benzene hexachloride).$3$. Therefore,$A$ is $HCB$ and $B$ is $BHC$.

Identify products $A$ and $B$ in the following reaction scheme:
Reaction $1$: Benzene + $Cl_2$ (excess) $\xrightarrow{FeCl_3}$ $A$
Reaction $2$: Benzene + $Cl_2$ (excess) $\xrightarrow{h\nu}$ $B$

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Identify products $A$ and $B$ in the following reaction scheme:Reaction $1$: Benzene + $Cl_2$ (excess) $\xrightarrow{FeCl_3}$ $A$Reaction $2$: Benzene + $Cl_2$ (excess) $\xrightarrow{h\nu}$ $B$