What are X and Y in the following reaction?(C | vedclass

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(B) The reaction of an ether with $HI$ involves the protonation of the ether oxygen followed by a nucleophilic attack by the iodide ion.In the case of

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$(H_3C)_3COH \quad CH_3I$

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(B) The reaction of an ether with $HI$ involves the protonation of the ether oxygen followed by a nucleophilic attack by the iodide ion.In the case of tert-butyl methyl ether,the protonation occurs at the oxygen atom.Since the tert-butyl group can form a stable carbocation,the reaction proceeds via an $S_N1$ mechanism (or $S_N2$ depending on conditions,but the products are consistent).The iodide ion attacks the less sterically hindered methyl group,leading to the formation of tert-butyl alcohol and methyl iodide.Thus,$X = (CH_3)_3COH$ and $Y = CH_3I$.

What are $X$ and $Y$ in the following reaction?
$(CH_3)_3COCH_3 + HI \rightarrow X + Y$

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What are $X$ and $Y$ in the following reaction?$(CH_3)_3COCH_3 + HI \rightarrow X + Y$