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The reactant is $4-hydroxy-3-methylbenzenesulfonic acid$. The reaction with $Br_2$ in $H_2O$ (bromine water) is an electrophilic aromatic substitution. The $-OH$ group is strongly activating and ortho/para directing. The $-SO_3H$ group is a good leaving group in the presence of excess bromine water. Predict the product of the reaction: $\xrightarrow{Br_2, H_2O} \text{Product}$

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Which of the following has the highest $pK_{a}$ value?

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An aromatic compound $X$ when heated with $Zn$ powder gives benzoic acid,but when heated with soda lime,it gives phenol. Identify the compound $X$.

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Identify the product in the following reaction:
Phenol + $CHCl_3 + NaOH \rightarrow \text{Product}$

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