What are X and Y respectively in the followin | vedclass

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(D) $1$. The reaction of benzenediazonium salt $(C_6H_5N_2^+X^-)$ with ethanol $(C_2H_5OH)$ reduces the diazonium group to benzene,but in the presence

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Phenol,Salicylaldehyde

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(D) $1$. The reaction of benzenediazonium salt $(C_6H_5N_2^+X^-)$ with ethanol $(C_2H_5OH)$ reduces the diazonium group to benzene,but in the presence of water or ethanol,it typically forms phenol $(C_6H_5OH)$ as the major product. Given the subsequent reaction,$X$ is phenol $(C_6H_5OH)$.$2$. The reaction of phenol $(C_6H_5OH)$ with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ is the Gattermann-Koch formylation reaction,which introduces a formyl group $(-CHO)$ at the ortho position of the phenol ring,resulting in salicylaldehyde ($2$-hydroxybenzaldehyde).$3$. Therefore,$X$ is phenol and $Y$ is salicylaldehyde.

What are $X$ and $Y$ respectively in the following reaction sequence?
$C_6H_5N_2^+X^-$ $\xrightarrow{C_2H_5OH} X$ $\xrightarrow[\text{anhy. } AlCl_3]{CO, HCl} Y$

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What are $X$ and $Y$ respectively in the following reaction sequence?$C_6H_5N_2^+X^-$ $\xrightarrow{C_2H_5OH} X$ $\xrightarrow[\text{anhy. } AlCl_3]{CO, HCl} Y$