What are A and B in the following reaction se | vedclass

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Question

(A) The reaction sequence is as follows:$1$. $CH_3COOH$ reacts with $P_2O_5$ under heating $(\Delta)$ to form acetic anhydride $(X)$ via dehydration.$

Vedclass · Accepted Answer

$A = P_2O_5, \Delta; B = 	ext{2-acetoxybenzoic acid}$

Vedclass · Answer

(A) The reaction sequence is as follows:$1$. $CH_3COOH$ reacts with $P_2O_5$ under heating $(\Delta)$ to form acetic anhydride $(X)$ via dehydration.$2$. Acetic anhydride $(X)$ then reacts with salicylic acid $(Y)$ in the presence of an acid catalyst $(H^ )$ to undergo acetylation of the phenolic $-OH$ group.$3$. This reaction produces $2-	ext{acetoxybenzoic acid}$,commonly known as aspirin $(B)$,which acts as an analgesic drug.Therefore,$A = P_2O_5, \Delta$ and $B = 	ext{2-acetoxybenzoic acid}$.

What are $A$ and $B$ in the following reaction sequence?
$CH_3COOH$ $\xrightarrow{A} X$ $\xrightarrow[H^{+}]{Y} \underset{\text{(Analgesic drug)}}{B}$

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What are $A$ and $B$ in the following reaction sequence?$CH_3COOH$ $\xrightarrow{A} X$ $\xrightarrow[H^{+}]{Y} \underset{\text{(Analgesic drug)}}{B}$