What are X and Y respectively in the followin | vedclass

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(A) The first step is the aromatization of $n$-heptane to toluene. $n$-Alkanes having six or more carbon atoms,when heated to $773 \ K$ at $10-20 \ at

Vedclass · Accepted Answer

$Cr_2O_3, 773 \ K, 10-20 \ atm; 	ext{Benzyl bromide}$

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(A) The first step is the aromatization of $n$-heptane to toluene. $n$-Alkanes having six or more carbon atoms,when heated to $773 \ K$ at $10-20 \ atm$ pressure in the presence of oxides of vanadium $(V_2O_5)$,molybdenum $(Mo_2O_3)$,or chromium $(Cr_2O_3)$ supported over alumina,undergo dehydrogenation and cyclization to form benzene and its homologs. Thus,$X$ is $Cr_2O_3, 773 \ K, 10-20 \ atm$.The second step is the free radical bromination of the side chain of toluene. Treatment of toluene with $Br_2$ in the presence of heat (or light) leads to the substitution of a hydrogen atom on the methyl group,resulting in the formation of benzyl bromide $(C_6H_5CH_2Br)$ as $Y$.

What are $X$ and $Y$ respectively in the following reaction sequence?

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