What are X and Y respectively in the followin | vedclass

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(A) The reduction of $2$-butyne with $Na / NH_3$ (liq.) (Birch reduction) proceeds via anti-addition to yield the $E$-product (trans$-2-$butene). The

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$Na / NH_3$ (liq.) and $Pd / BaSO_4 + H_2$

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(A) The reduction of $2$-butyne with $Na / NH_3$ (liq.) (Birch reduction) proceeds via anti-addition to yield the $E$-product (trans$-2-$butene). The reduction of $2$-butyne with $Pd / BaSO_4 + H_2$ (Lindlar's catalyst) proceeds via syn-addition to yield the $Z$-product (cis$-2-$butene). According to the reaction scheme: $2$-butyne $\xrightarrow{X} E$-product implies $X = Na / NH_3$ (liq.). $2$-butyne $\xrightarrow{Y} Z$-product implies $Y = Pd / BaSO_4 + H_2$. Therefore,$X$ and $Y$ are $Na / NH_3$ (liq.) and $Pd / BaSO_4 + H_2$ respectively.

What are $X$ and $Y$ respectively in the following reaction?
$Z$-product $\stackrel{Y}{\longleftarrow} 2$-butyne $\stackrel{X}{\longrightarrow} E$-product

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What are $X$ and $Y$ respectively in the following reaction? $Z$-product $\stackrel{Y}{\longleftarrow} 2$-butyne $\stackrel{X}{\longrightarrow} E$-product