What are X and Y in the following reaction se | vedclass

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(A) The reaction sequence is as follows:$1$. Dehydrogenation of $C_5H_{12}O$ (a primary or secondary alcohol) with $Cu$ at $573 \ K$ gives an alkene $

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Acetone + Acetaldehyde

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(A) The reaction sequence is as follows:$1$. Dehydrogenation of $C_5H_{12}O$ (a primary or secondary alcohol) with $Cu$ at $573 \ K$ gives an alkene $(C_5H_{10})$.$2$. Ozonolysis of the alkene $(C_5H_{10})$ followed by reductive workup $(Zn/H_2O)$ yields carbonyl compounds $X$ and $Y$.$3$. Considering the options,if the alkene is $2$-methylbut-$2$-ene $(CH_3-C(CH_3)=CH-CH_3)$,its ozonolysis gives acetone $(CH_3COCH_3)$ and acetaldehyde $(CH_3CHO)$.$4$. Thus,$X$ and $Y$ are acetone and acetaldehyde.

What are $X$ and $Y$ in the following reaction sequence?
$C_5H_{12}O$ $\xrightarrow[573 \ K]{Cu} C_5H_{10}$ $\xrightarrow[\text{(ii) } Zn/H_2O]{\text{(i) } O_3} X + Y$

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What are $X$ and $Y$ in the following reaction sequence?$C_5H_{12}O$ $\xrightarrow[573 \ K]{Cu} C_5H_{10}$ $\xrightarrow[\text{(ii) } Zn/H_2O]{\text{(i) } O_3} X + Y$