What are the number of octahedral and tetrahedral voids in $0.3 \ mol$ of a substance respectively,if it forms an $hcp$ structure?

  • A
    $1.8066 \times 10^{23}$ and $3.6132 \times 10^{23}$
  • B
    $3.6132 \times 10^{23}$ and $1.8066 \times 10^{23}$
  • C
    $6.022 \times 10^{23}$ and $12.044 \times 10^{23}$
  • D
    $12.044 \times 10^{23}$ and $6.022 \times 10^{23}$

Explore More

Similar Questions

$A$ compound forms a hexagonal close-packed $(HCP)$ structure. What is the total number of voids in $0.5 \ mol$ of it? How many of these are tetrahedral voids?

The volume occupied by the atoms in a unit cell of hexagonal close packing $(HCP)$ or cubic close packing $(CCP)$ is equal to:

The number of tetrahedral and octahedral voids in a $CCP$ unit cell are respectively:

Calculate the number and position of tetrahedral and octahedral voids in a $ccp$ or $fcc$ structure.

Difficult
View Solution

In a face-centred cubic arrangement of $A$ and $B$ atoms,$A$ atoms are at the corners of the unit cell and $B$ atoms are at the face centres. If one of the $A$ atoms is missing from one corner of the unit cell,what is the simplest formula of the compound?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo