What are the products B and C in the followin | vedclass

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Question

(C) The reaction sequence is as follows:$1$. Cyclohexanecarboxylic acid reacts with $NaOH$ (a base) to form its sodium salt,$B$,which is sodium cycloh

Vedclass · Accepted Answer

$(B) = 	ext{sodium cyclohexanecarboxylate}, (C) = 	ext{cyclohexane}$

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. Cyclohexanecarboxylic acid reacts with $NaOH$ (a base) to form its sodium salt,$B$,which is sodium cyclohexanecarboxylate $(C_6H_{11}COONa)$.$2$. The sodium salt $B$ then undergoes decarboxylation when heated with soda lime $(NaOH + CaO)$. This process removes the $-COONa$ group and replaces it with a hydrogen atom,resulting in the formation of cyclohexane $(C_6H_{12})$ as product $C$.

What are the products $B$ and $C$ in the following reaction sequence?

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