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(B) When $CO_{2}$ is passed through slaked lime $(Ca(OH)_{2})$,it first forms a white precipitate of calcium carbonate $(CaCO_{3})$:$Ca(OH)_{2} + CO_{

Vedclass · Accepted Answer

$CaCO_{3}, Ca(HCO_{3})_{2}$

Vedclass · Answer

(B) When $CO_{2}$ is passed through slaked lime $(Ca(OH)_{2})$,it first forms a white precipitate of calcium carbonate $(CaCO_{3})$:$Ca(OH)_{2} + CO_{2} \longrightarrow CaCO_{3} \downarrow + H_{2}O$When excess $CO_{2}$ is passed,the calcium carbonate reacts further to form soluble calcium bicarbonate $(Ca(HCO_{3})_{2})$:$CaCO_{3} + CO_{2} + H_{2}O \longrightarrow Ca(HCO_{3})_{2}$

What are the products formed in sequence when excess of $CO_{2}$ is passed in slaked lime?

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