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(C) The reaction involves the cleavage of an aryl alkyl ether with excess $HBr$ under heating conditions. In the reactant $C_6H_5-O-CH_2CH_2OH$,the $C

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$Phenol + BrCH_2CH_2Br$

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(C) The reaction involves the cleavage of an aryl alkyl ether with excess $HBr$ under heating conditions. In the reactant $C_6H_5-O-CH_2CH_2OH$,the $C-O$ bond between the phenyl ring and the oxygen atom has partial double bond character due to resonance,making it very strong and resistant to cleavage. Therefore,the $HBr$ attacks the alkyl $C-O$ bond. The oxygen atom is protonated by $H^+$,and then the bromide ion $(Br^-)$ attacks the alkyl carbon,leading to the formation of phenol $(C_6H_5OH)$ and $1,2-dibromoethane$ $(BrCH_2CH_2Br)$ because the initial product $BrCH_2CH_2OH$ reacts further with excess $HBr$ to form $BrCH_2CH_2Br$.

What are the products of the following reaction?

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