What change does not occur when K_2Cr_2O_7 re | vedclass

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Question

(C) When $K_2Cr_2O_7$ reacts with $H_2O_2$ in an acidic medium,it forms $CrO_5$ (chromium pentoxide),which has a deep blue colour.The reaction is: $Cr

Vedclass · Accepted Answer

$O.S.$ of $Cr$ atom remains constant

Vedclass · Answer

(C) When $K_2Cr_2O_7$ reacts with $H_2O_2$ in an acidic medium,it forms $CrO_5$ (chromium pentoxide),which has a deep blue colour.The reaction is: $Cr_2O_7^{2-} + 2H^+ + 4H_2O_2 \rightarrow 2CrO_5 + 5H_2O$.In $K_2Cr_2O_7$,the oxidation state $(O.S.)$ of $Cr$ is $+6$.In $CrO_5$,the oxidation state $(O.S.)$ of $Cr$ is also $+6$.Therefore,the oxidation state of the $Cr$ atom remains constant.Since the question asks which change does $NOT$ occur,and the oxidation state does not change,option $C$ is the correct statement regarding what does not happen (i.e.,it does not change,so it remains constant is a true statement,but the question asks for the change that does not occur. Actually,the change in $O.S.$ does not occur,so $C$ is the correct answer).

Column-$I$ [Type of reaction]	Column-$II$ [Example]
$I$. Intermolecular redox reaction	$A$. $CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O$
$II$. Intramolecular redox reaction	$B$. $NH_4NO_2 \rightarrow N_2 + 2H_2O$
$III$. Disproportionation reaction	$C$. $2H_2O_2 \rightarrow 2H_2O + O_2$
$IV$. Comproportionation reaction	$D$. $KClO_3 \rightarrow KCl + \frac{3}{2}O_2$

What change does not occur when $K_2Cr_2O_7$ reacts with $H_2O_2$ solution in an acidic medium?

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