What effect occurs on the frequency of a pend | vedclass

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(B) The frequency of a simple pendulum is given by the formula $n = \frac{1}{2\pi} \sqrt{\frac{g}{l}}$,which implies $n \propto \sqrt{g}$.When a pendu

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Decreases

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(B) The frequency of a simple pendulum is given by the formula $n = \frac{1}{2\pi} \sqrt{\frac{g}{l}}$,which implies $n \propto \sqrt{g}$.When a pendulum is taken deep into a mine at a depth $d$,the acceleration due to gravity $g'$ is given by $g' = g \left( 1 - \frac{d}{R} \right)$,where $R$ is the radius of the Earth.Since $g' Because the frequency $n$ is directly proportional to the square root of $g$,a decrease in $g$ leads to a decrease in the frequency of the pendulum.

What effect occurs on the frequency of a pendulum if it is taken from the earth's surface to deep into a mine?

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