What happens when methane reacts with concentrated $HNO_3$ at high temperature?
- ANitromethane is formed
- BMethanol is formed
- C$CO_2$ and $H_2O$ are formed
- D$CO$ and $H_2O$ are formed
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Similar Questions
Which metal catalyzed reaction would release the maximum amount of heat per $CH_2$ unit?
Difficult
View SolutionWhich type of reaction occurs when $(CH_{3})_{3}CH$ reacts with $KMnO_{4}$? Explain.
Medium
View SolutionWhich of the following statements is true?
Medium
View Solution$CH_3-CH_2-CH_2-CH_2-CH_3 \xrightarrow{CH_2N_2/\Delta} \text{Product}$.
Which of the following product$(s)$ can be obtained in the above reaction?
Which of the following product$(s)$ can be obtained in the above reaction?
Difficult
View SolutionMatch the column and find the correct answer:
Column-$I$ Column-$II$ $i$. $n$-Butane $\to 2$-methylpropane $A$. Free radical substitution $ii$. $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$ $B$. Wurtz reaction $iii$. $R-COONa \xrightarrow{\text{soda-lime}} R-H$ $C$. Isomerism $iv$. $R-X + Na \xrightarrow{\text{Ether}} R-R$ $D$. Decarboxylation
| Column-$I$ | Column-$II$ |
| $i$. $n$-Butane $\to 2$-methylpropane | $A$. Free radical substitution |
| $ii$. $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$ | $B$. Wurtz reaction |
| $iii$. $R-COONa \xrightarrow{\text{soda-lime}} R-H$ | $C$. Isomerism |
| $iv$. $R-X + Na \xrightarrow{\text{Ether}} R-R$ | $D$. Decarboxylation |
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