What happens when zinc granules are treated with dilute solutions of $H_{2}SO_{4}$,$HCl$,and $HNO_{3}$? Also,write the chemical equations if a reaction occurs.

(N/A) The reaction of $Zn$ granules with:
$(a)$ Dilute $H_{2}SO_{4}$:
$Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)$
$(b)$ Dilute $HCl$:
$Zn(s) + 2HCl(aq) \rightarrow ZnCl_{2}(aq) + H_{2}(g)$
$(c)$ Dilute $HNO_{3}$:
Reaction with dilute $HNO_{3}$ is different compared to other acids because nitric acid is a strong oxidizing agent. It oxidizes the $H_{2}$ gas evolved to $H_{2}O$ and gets reduced itself to nitrogen oxides (like $N_{2}O$,$NO$,or $NO_{2}$ depending on concentration). For very dilute $HNO_{3}$,the reaction is:
$4Zn(s) + 10HNO_{3}(aq) \rightarrow 4Zn(NO_{3})_{2}(aq) + 5H_{2}O(l) + N_{2}O(g)$