What happens when $CO_2$ is passed through lime water in limited amount?
(N/A) When $CO_2$ is passed through lime water in limited amount,the lime water turns milky due to the formation of insoluble white precipitates of calcium carbonate.
The chemical reaction is as follows:
$Ca(OH)_2(aq) + CO_2(g) \to CaCO_3(s) \downarrow + H_2O(l)$
The chemical reaction is as follows:
$Ca(OH)_2(aq) + CO_2(g) \to CaCO_3(s) \downarrow + H_2O(l)$
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Similar Questions
Fill in the missing data in the following table:
Name of the salt Formula Base Acid $(i)$ Ammonium chloride $NH_{4}Cl$ $NH_{4}OH$ - $(ii)$ Copper sulphate - - $H_{2}SO_{4}$ $(iii)$ Sodium chloride $NaCl$ $NaOH$ - $(iv)$ Magnesium nitrate $Mg(NO_{3})_{2}$ - $HNO_{3}$ $(v)$ Potassium sulphate $K_{2}SO_{4}$ - - $(vi)$ Calcium nitrate $Ca(NO_{3})_{2}$ $Ca(OH)_{2}$ -
| Name of the salt | Formula | Base | Acid |
| $(i)$ Ammonium chloride | $NH_{4}Cl$ | $NH_{4}OH$ | - |
| $(ii)$ Copper sulphate | - | - | $H_{2}SO_{4}$ |
| $(iii)$ Sodium chloride | $NaCl$ | $NaOH$ | - |
| $(iv)$ Magnesium nitrate | $Mg(NO_{3})_{2}$ | - | $HNO_{3}$ |
| $(v)$ Potassium sulphate | $K_{2}SO_{4}$ | - | - |
| $(vi)$ Calcium nitrate | $Ca(NO_{3})_{2}$ | $Ca(OH)_{2}$ | - |
Difficult
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The separation of $H^+$ ions from $HCl$ molecules can occur in the absence of water.
The separation of $H^+$ ions from $HCl$ molecules can occur in the absence of water.
Easy
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View SolutionWhich of the following statements is correct about an aqueous solution of an acid and of a base?
$(i)$ Higher the $pH$,stronger the acid
$(ii)$ Higher the $pH$,weaker the acid
$(iii)$ Lower the $pH$,stronger the base
$(iv)$ Lower the $pH$,weaker the base
$(i)$ Higher the $pH$,stronger the acid
$(ii)$ Higher the $pH$,weaker the acid
$(iii)$ Lower the $pH$,stronger the base
$(iv)$ Lower the $pH$,weaker the base
Medium
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