What is B in the given reaction?C_2H_5Br xrig | vedclass

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Question

(A) The reaction $C_2H_5Br \xrightarrow{	ext{excess } NH_3} A$ represents the ammonolysis of an alkyl halide,where $A$ is ethylamine $(CH_3CH_2NH_2)$

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Propanamide $(CH_3CH_2CONH_2)$

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(A) The reaction $C_2H_5Br \xrightarrow{	ext{excess } NH_3} A$ represents the ammonolysis of an alkyl halide,where $A$ is ethylamine $(CH_3CH_2NH_2)$.The reaction $B \xrightarrow{Br_2/KOH} A$ is the Hofmann bromamide degradation reaction,which converts an amide into a primary amine with one carbon atom less than the original amide.Since $A$ is ethylamine $(CH_3CH_2NH_2)$,which has $2$ carbon atoms,the amide $B$ must have $3$ carbon atoms.Therefore,$B$ is propanamide $(CH_3CH_2CONH_2)$.

What is $B$ in the given reaction?
$C_2H_5Br \xrightarrow{\text{excess } NH_3} A \xleftarrow{Br_2/KOH} B$

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What is $B$ in the given reaction?$C_2H_5Br \xrightarrow{\text{excess } NH_3} A \xleftarrow{Br_2/KOH} B$