What is E?Cyclohexanone xrightarrow{Br_2 + CH | vedclass

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(A) $1$. Cyclohexanone reacts with $Br_2$ in $CH_3COOH$ to form $2$-bromocyclohexanone $(A)$.$2$. $A$ undergoes dehydrohalogenation with $Alc. KOH$ to

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$3-$bromo$-1-$methylcyclohex$-1-$ene

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(A) $1$. Cyclohexanone reacts with $Br_2$ in $CH_3COOH$ to form $2$-bromocyclohexanone $(A)$.$2$. $A$ undergoes dehydrohalogenation with $Alc. KOH$ to form cyclohex$-2-$en$-1-$one $(B)$.$3$. $B$ reacts with $CH_3MgBr$ followed by $H_2O$ ($1$,$2$-addition) to form $1$-methylcyclohex$-2-$en$-1-$ol $(C)$.$4$. $C$ undergoes acid-catalyzed dehydration $(H^{\oplus} + \Delta)$ to form $1$-methylcyclohexa$-1,3-$diene $(D)$.$5$. $D$ reacts with $1 	ext{ mole}$ of $HBr$ via thermodynamic control ($T$.$C$.$P$) to form the most stable product,which is $3$-bromo-$1$-methylcyclohex-$1$-ene $(E)$.

What is $E$?
Cyclohexanone $\xrightarrow{Br_2 + CH_3COOH} A$ $\xrightarrow{Alc. KOH} B$ (Product with six-membered ring) $\xrightarrow[(2) H_2O]{(1) CH_3MgBr} C$ $\xrightarrow{H^{\oplus} + \Delta} D$ $\xrightarrow{HBr (1 \text{ mole})} E$

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What is $E$?Cyclohexanone $\xrightarrow{Br_2 + CH_3COOH} A$ $\xrightarrow{Alc. KOH} B$ (Product with six-membered ring) $\xrightarrow[(2) H_2O]{(1) CH_3MgBr} C$ $\xrightarrow{H^{\oplus} + \Delta} D$ $\xrightarrow{HBr (1 \text{ mole})} E$