The reaction of 2,3-dichlorobutane (as shown | vedclass

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(C) The reaction of $2,3$-dichlorobutane with $Zn$ dust is a dehalogenation reaction. In the given stereoisomer (meso-form),the two $Cl$ atoms are ant

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Melting point is greater than its geometrical isomer

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(C) The reaction of $2,3$-dichlorobutane with $Zn$ dust is a dehalogenation reaction. In the given stereoisomer (meso-form),the two $Cl$ atoms are anti to each other,leading to the formation of $trans-but-2-ene$. $trans-but-2-ene$ has a center of symmetry,which makes its dipole moment equal to zero. $trans-isomers$ are more symmetrical than $cis-isomers$,allowing them to pack better in the crystal lattice,resulting in a higher melting point. Therefore,the statement that the melting point is greater than its geometrical isomer $(cis-but-2-ene)$ is correct.

The reaction of $2,3$-dichlorobutane (as shown in the image) with $Zn$ dust and heat produces an alkene. Which of the following statements is correct about the product formed?

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