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(A) The reaction of $1	ext{-methylcyclohexene}$ with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.In this reaction,the electro

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$2-$bromo$-1-$methylcyclohexan$-1-$ol

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(A) The reaction of $1	ext{-methylcyclohexene}$ with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.In this reaction,the electrophile $Br^+$ attacks the double bond to form a cyclic bromonium ion intermediate.Water $(H_2O)$,acting as a nucleophile,attacks the more substituted carbon of the bromonium ion because it can better stabilize the partial positive charge in the transition state.This leads to the formation of $2	ext{-bromo-1-methylcyclohexan-1-ol}$ as the major product,where the $-OH$ group is attached to the more substituted carbon and the $-Br$ atom is attached to the less substituted carbon.

What is the major product of the following reaction?
$1\text{-methylcyclohexene} \xrightarrow{Br_2, H_2O} ?$

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What is the major product obtained in the following reaction?

$2-$chloro$-2-$methylpentane on reaction with sodium methoxide in methanol yields:
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In the reaction shown,the major product obtained is:

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What is the major product of the following reaction?$1\text{-methylcyclohexene} \xrightarrow{Br_2, H_2O} ?$