What is the percentage of Fe^{+3} among catio | vedclass

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(B) Let the amount of $Fe^{+3}$ be $x$ and $Fe^{+2}$ be $(0.93 - x)$.The total charge must be zero for the neutral compound $Fe_{0.93}O_{1.00}$.$3x +

Vedclass · Accepted Answer

$14/93 	imes 100$

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(B) Let the amount of $Fe^{+3}$ be $x$ and $Fe^{+2}$ be $(0.93 - x)$.The total charge must be zero for the neutral compound $Fe_{0.93}O_{1.00}$.$3x + 2(0.93 - x) - 2 = 0$$3x + 1.86 - 2x - 2 = 0$$x = 0.14$The fraction of $Fe^{+3}$ ions among total iron cations is $\frac{0.14}{0.93}$.Therefore,the percentage of $Fe^{+3}$ is $\frac{0.14}{0.93} 	imes 100 = \frac{14}{93} 	imes 100$.

What is the percentage of $Fe^{+3}$ among cations in $Fe_{0.93}O_{1.00}$?

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