(D) $H_2SO_4 \to 2H^{+} + SO_4^{2-}$ Since $H_2SO_4$ is a strong diprotic acid,it dissociates completely as $H_2SO_4 \to 2H^{+} + SO_4^{2-}$. For a $1

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(D) $H_2SO_4 \to 2H^{+} + SO_4^{2-}$ Since $H_2SO_4$ is a strong diprotic acid,it dissociates completely as $H_2SO_4 \to 2H^{+} + SO_4^{2-}$. For a $1 \, M$ solution of $H_2SO_4$,the concentration of $H^{+}$ ions is $[H^{+}] = 2 \times 1 \, M = 2 \, M$. The $pH$ is calculated as $pH = - \log [H^{+}]$. $pH = - \log(2) = -0.3010$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)pH of strong Acids and strong Bases

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What is the $pH$ value of $1 \, M \, H_2SO_4$?

AIIMS 2008 All AIIMS

A
$0$
B
$-0.213$
C
$-2$
D
$-0.3010$

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6-2.Equilibrium-II (Ionic Equilibrium)

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pH of strong Acids and strong Bases

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What is the $pH$ value of $1 \, M \, H_2SO_4$?

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