What is the H.C.F. of frac{4}{9}, frac{10}{21 | vedclass

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(C) To find the $H.C.F.$ of fractions,we use the formula:$H.C.F. = \frac{H.C.F. 	ext{ of numerators}}{L.C.M. 	ext{ of denominators}}$Given fractions

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$\frac{2}{63}$

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(C) To find the $H.C.F.$ of fractions,we use the formula:$H.C.F. = \frac{H.C.F. 	ext{ of numerators}}{L.C.M. 	ext{ of denominators}}$Given fractions: $\frac{4}{9}, \frac{10}{21}, \frac{20}{63}$Step $1$: Find the $H.C.F.$ of the numerators $(4, 10, 20)$:Factors of $4 = 2 	imes 2$Factors of $10 = 2 	imes 5$Factors of $20 = 2 	imes 2 	imes 5$The common factor is $2$. So,$H.C.F. = 2$.Step $2$: Find the $L.C.M.$ of the denominators $(9, 21, 63)$:$9 = 3^2$$21 = 3 	imes 7$$63 = 3^2 	imes 7$$L.C.M. = 3^2 	imes 7 = 9 	imes 7 = 63$.Step $3$: Combine the results:$H.C.F. = \frac{2}{63}$.

What is the $H.C.F.$ of $\frac{4}{9}, \frac{10}{21}$ and $\frac{20}{63}$?

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