What is the actual volume occupied by water m | vedclass

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(A) The density of water is approximately $1 \ g/cm^3$. Thus,$20 \ cm^3$ of water has a mass of $20 \ g$.The molar mass of water $(H_2O)$ is $18 \ g/m

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$20$

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(A) The density of water is approximately $1 \ g/cm^3$. Thus,$20 \ cm^3$ of water has a mass of $20 \ g$.The molar mass of water $(H_2O)$ is $18 \ g/mol$.The number of moles of water is $n = \frac{20 \ g}{18 \ g/mol} = 1.11 \ mol$.The number of molecules is $1.11 	imes 6.022 	imes 10^{23} \approx 6.69 	imes 10^{23}$ molecules.However,in liquid water,the molecules are closely packed. The actual volume occupied by the molecules themselves is negligible compared to the total volume of the liquid because the intermolecular space is very small. For standard calculations in this context,the volume of the molecules is considered to be the volume of the liquid itself,which is $20 \ cm^3$.

List-$I$	List-$II$
$(a)$ $2 \text{ moles of ethene}$	$(i)$ $11.2 \text{ L volume at STP}$
$(b)$ $\text{Molar mass is equal to } 66 \text{ g}$	$(ii)$ $56 \text{ g}$
$(c)$ $1 \text{ g of } H_2$	$(iii)$ $12.04 \times 10^{23} \text{ molecules}$
$(d)$ $2 \text{ moles of water vapours}$	$(iv)$ $1.5 \text{ mole of } CO_2$

What is the actual volume occupied by water molecules present in $20 \ cm^3$ of water (in $cm^3$)?

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