What is the bond order of $B_{2}$ molecule?

The compound $(SiH_3)_3N$ is expected to be

The correct sequence of bond order is

The bond lengths of diatomic molecules of elements $X$,$Y$ and $Z$ respectively are $143 \text{ pm}$,$110 \text{ pm}$ and $121 \text{ pm}$. The atomic numbers of $X$,$Y$ and $Z$ respectively are:

Match the following:

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

The molecular orbital configuration of a diatomic molecule is
$\sigma 1s^2 \sigma^* 1s^2 \sigma 2s^2 \sigma^* 2s^2 \sigma 2p_x^2 \pi 2p_y^2 \pi 2p_z^2$
Its bond order is