What is the change in oxidation number of selenium in the following redox reaction?
$SeO_{3(aq)}^{2-} + Cl_{2(g)} + 2OH^- \longrightarrow SeO_{4(aq)}^{2-} + 2Cl_{(aq)}^- + H_2O$
$SeO_{3(aq)}^{2-} + Cl_{2(g)} + 2OH^- \longrightarrow SeO_{4(aq)}^{2-} + 2Cl_{(aq)}^- + H_2O$
- A$+2$ to $-2$
- B$-2$ to $+2$
- C$+4$ to $+6$
- D$+3$ to $+4$
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Medium
View SolutionWhat is the difference in oxidation number of $Mn$ in $KMnO_4$ and $MnO_2$?
What are the oxidation numbers of the underlined elements in each of the following and how do you rationalize your results?
$(1)$ $K\underline{I_3}$
$(2)$ $H_2\underline{S_4}O_6$
$(3)$ $\underline{Fe_3}O_4$
$(4)$ $\underline{C}H_3\underline{C}H_2OH$
$(5)$ $\underline{C}H_3\underline{C}OOH$
$(1)$ $K\underline{I_3}$
$(2)$ $H_2\underline{S_4}O_6$
$(3)$ $\underline{Fe_3}O_4$
$(4)$ $\underline{C}H_3\underline{C}H_2OH$
$(5)$ $\underline{C}H_3\underline{C}OOH$
Difficult
View SolutionIn the following reaction,assign the oxidation state of the underlined atom for the product of complete hydrolysis at $R.T.$:
$H\underline{N}O_4 + H_2O \longrightarrow HNO_3 + H_2O_2$
$H\underline{N}O_4 + H_2O \longrightarrow HNO_3 + H_2O_2$
Difficult
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