What is the change in temperature when work i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In an adiabatic process,there is no exchange of heat between the system and the surroundings,so $dQ = 0$.According to the first law of thermodynam

Vedclass · Accepted Answer

Temperature decreases

Vedclass · Answer

(B) In an adiabatic process,there is no exchange of heat between the system and the surroundings,so $dQ = 0$.According to the first law of thermodynamics,$dQ = dU + dW$,where $dU$ is the change in internal energy and $dW$ is the work done.Since $dQ = 0$,we have $0 = dU + dW$,which implies $dU = -dW$.When work is done by the gas,$dW > 0$.Therefore,$dU = -dW Since the internal energy of an ideal gas is directly proportional to its temperature $(U \propto T)$,a decrease in internal energy leads to a decrease in the temperature of the gas.

What is the change in temperature when work is done by a gas in an adiabatic process?

Similar Questions

Which of the following is true in the case of an adiabatic process, where $\gamma = C_p / C_V$?

An ideal gas is expanded adiabatically at an initial temperature of $300 \ K$ so that its volume is doubled. The final temperature of the hydrogen gas is $(\gamma = 1.40)$.

During adiabatic expansion,if the temperature of $3$ moles of a diatomic gas decreases by $50^{\circ} C$,then the work done by the gas is (where $R$ is the Universal gas constant). (in $R$)

An ideal gas at $27^{\circ} C$ is compressed adiabatically to $8/27$ of its original volume. If $\gamma = 5/3$,the rise in temperature of the gas is: (in $K$)

$A$ reversible adiabatic path on a $P-V$ diagram for an ideal gas passes through state $A$ where $P = 0.7 \times 10^5 \, N/m^2$ and $V = 0.0049 \, m^3$. The ratio of specific heats of the gas is $1.4$. The slope of the path at $A$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module