What is the change in the oxidation state of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In an acidic medium,the permanganate ion $(MnO_4^{-})$ acts as a strong oxidizing agent and reacts with hydrogen peroxide $(H_2O_2)$.The balanced

Vedclass · Accepted Answer

$7 \rightarrow 2$

Vedclass · Answer

(C) In an acidic medium,the permanganate ion $(MnO_4^{-})$ acts as a strong oxidizing agent and reacts with hydrogen peroxide $(H_2O_2)$.The balanced chemical equation for this reaction is: $2MnO_4^{-} + 5H_2O_2 + 6H^{+} \rightarrow 2Mn^{2+} + 5O_2 + 8H_2O$.In $MnO_4^{-}$,the oxidation state of $Mn$ is calculated as: $x + 4(-2) = -1$,which gives $x = +7$.In the product $Mn^{2+}$,the oxidation state of $Mn$ is $+2$.Therefore,the oxidation state of $Mn$ changes from $+7$ to $+2$.

What is the change in the oxidation state of $Mn$ in the reaction of $MnO_4^{-}$ with $H_2O_2$ in acidic medium?

Similar Questions

The oxidation state of chlorine in perchloric acid $(HClO_4)$ is:

Calculate the oxidation number of sulfur,chromium,and nitrogen in $H_2SO_5$,$Cr_2O_7^{2-}$,and $NO_3^-$. Suggest the structures of these compounds and explain the fallacy in the direct calculation of the oxidation number for $H_2SO_5$.

What is the oxidation number of sulfur in $Na_2S_4O_6$?

The oxidation number of $H$ in $KH$,$MgH_2$,and $NaOH$ are respectively

The oxidation number of $Cr$ in $K_3CrO_8$ is $+5$. How many peroxy linkages are present in this molecule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module